2x+1=(x+2)^(1/2)

Solution for 2x+1=(x+2)^(1/2) equation:

2x+1=(x+2)^(1/2)

We move all terms to the left:

2x+1-((x+2)^(1/2))=0

We add all the numbers together, and all the variables

2x-((x+2)^(+1/2))+1=0

We multiply all the terms by the denominator


2x*2))-((x+1+2)^(+1*2))=0

We add all the numbers together, and all the variables

2x*2))-((x+3)^2)=0

We add all the numbers together, and all the variables

2x*2))-((x=0

Wy multiply elements

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$